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MHT CET202122 Sep 2021Morning ShiftMathematicsVector AlgebraActual

The Cartesian equation of a line is 3 x+1=6 y-2=-z+1 , then its vector equation is

Options

  1. Ar = ( -1 3 i + 1 3 j + k )+ (2 i - j -6 k )
  2. Br =(- i +2 j - k )+ (3 i +6 j - k )
  3. Cr = ( -1 3 i + 1 3 j + k )+ (2 i - j +6 k )
  4. Dr = ( -1 3 i + 1 3 j + k )+ (2 i + j +6 k )

Correct answer

D. r = ( -1 3 i + 1 3 j + k )+ (2 i + j +6 k )

Step-by-step solution

aligned & 3 x+1=6 y-2=-z+1 & 3 (x+ 1 3 )=6 (y- 2 6 )=-(z-1) & (x+ 1 3 ) ( 1 3 ) = (y- 1 3 ) ( 1 6 ) = (z-1) (-1) d.r.s. are 2,1,-6 & Thus r = (- 1 3 i + 1 3 j + k )+ (2 i + j -6 k ) aligned

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