The position vector of the point of intersection of the medians of a triangle, whose vertices are A (1,2,3), B (1,0,3) and C (4,1,-3) is

Step-by-step solution

Let M be the mid point of BC and N be the mid point of AC . M = ( 5 2 , 1 2 , 0 ) We know that centroid G divides AM internally in the ratio 2: 1 aligned & G= (1)(1)+(2) ( 5 2 ) 2+1 , (1)(2)+(2) ( 1 2 ) 2+1 , (1)(3)+0 2+1 & G=(2,1,1) aligned