Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
AP EAMCET202017 Sep 2020Morning ShiftMathematicsBinomial TheoremActual

The constant term in the expansion of ( ( x 2 + 1 x + 2 )^5 ) is ( a 2 2 ), then (a= )

Options

  1. A7
  2. B69
  3. C63
  4. D65

Correct answer

C. 63

Step-by-step solution

( aligned & ( x 2 + 1 x + 2 )^5 & ( x 2 + 1 x )¹⁰= ( x+ 2 2 x )¹⁰ (x+ 2 )¹⁰ 32 x^5 aligned ) Forms constant term in the expansion ( array r = Coefficient of x^5 in (x+ 2 )¹⁰ 32 ¹⁰ C₅ 4 2 32 = a 2 2 (a=63) array )

Practice Binomial Theorem on Quantrex Academy →

More from Binomial Theorem

If n 13 , n 14 and n 15 are in arithmetic progression, then the positive integer value of ' n ' can be 2026If the coefficients of x^2 and x^3 in the expansion of (3 + kx)^9 are equal, then the value of ' k ' is 2026The remainder when 7¹⁰³ is divided by 25 is 2026_ r=1 ¹⁵ r^2 ( ¹⁵ C_r 15 r-1 )= 20251 81^ n - ^ 2 n C ₁ 10 81^ n + ^ 2 n C ₂ 10^2 81^ n - + 10^ 2 n 81^ n = 2025If x is positive real number and the first negative term in the expansion of (1+ x )^ 27 / 5 is t _ k then k = 2025In the binomial expansion of (p-q)¹⁴ , if the sum of 7^ th term and 8^ th term is zero, then p+q p-q = 2025The numerically greatest term in the expansion of (x+3 y)¹³ , when x= 1 2 and y= 1 3 is 2025 Full Binomial Theorem list All AP EAMCET PYQs