AP EAMCET201921 Apr 2019Morning ShiftMathematicsBinomial TheoremActual
Let a₀, a₁, a₂, a_n R be in an arithmetic progression and let C₀, C₁, C₂, , C_n be the binomial coefficients. Then _ k=0 ^n a_k C_k=
Options
- A1 2 (a₀+a_n )
- B(a₀+a_n ) 2^ n-1
- C(a₀+a_n )
- D0
Correct answer
B. (a₀+a_n ) 2^ n-1
Step-by-step solution
aligned _ k=0 ^n a_k C_k=a₀ C₀+a₁ C₁+a₂ C₂ & + +a_n C_n =a₀ C₀+ (a₀+d ) C₁ & + (a₀+2 d ) C₂ & + + (a₀+n d ) C_n aligned Where d is an common difference of an AP aligned = & a₀ (C₀+C₁+ +C_n )+ & d (C₁+2 C₂+3 C₃+ + ^n C_n ) = & a₀ 2^n+d (n 2^ n-1 ) = & 2^ n-1 [2 a₀+n d ]= (a₀+a_n ) 2^ n-1 aligned