MHT CET202520 Apr 2025Evening ShiftPhysicsElectromagnetic WavesActual
A parallel plate capacitor with plate area A and plate separation d is charged by constant current I. A plane surface of area A / 2 , parallel to the plates is drawn simultaneously between the plates. The displacement current through this area is
Options
- AI
- BI 2
- CI 4
- DI 8
Correct answer
B. I 2
Step-by-step solution
The conduction current I charging a parallel plate capacitor equals the total displacement current I_d between the plates, so I_d = I . The uniform displacement current density is J_d = I/A . For a parallel surface with area A' = A/2 , the displacement current is I_ d' = J_d A' = (I/A) (A/2) = I/2 . Final answer: B