With a resistance of ‘X’ in the left gap and a resistance of 9 Ω in the right gap of meter bridge, the balance point is obtained at 40 cm from the left end. In what way and to which resistance 3 Ω resistance be connected to obtained the balance at 50 cm from the left end?

Step-by-step solution

The balance condition of bridge is shown below in the first case Then, X 9 = 40 60 ⇒ X = 2 3 × 9 = 6 Ω To get the balance point at 50 cm from left end, the balanced, condition becomes, X ' 9 = 50 50 = 1 ⇒ X ' = 9 Ω As, in series combinations resistances are added, so to get 9 Ω at left gap the 3 Ω resistance should be added in series with X Ω 6 + 3 = 9 Ω .