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MHT CET202525 Apr 2025Evening ShiftPhysicsGravitationActual

The depth at which the value of acceleration due to gravity becomes ( 1 n ) times the value at the surface of the earth is ( R= radius of the earth)

Options

  1. AR(n-1) n
  2. BR(n+1) n
  3. CRn ( n -1)
  4. DR n

Correct answer

A. R(n-1) n

Step-by-step solution

The acceleration due to gravity at depth d below Earth's surface is given by g' = g (1 - d R ) , where g is the surface gravity and R is Earth's radius. Given that g' = g n , we substitute into the formula: g n = g (1 - d R ) Dividing both sides by g : 1 n = 1 - d R Solving for d : d R = 1 - 1 n = n-1 n d = R ( n-1 n ) This matches option A .

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