MHT CET202416 May 2024Evening ShiftPhysicsGravitationActual
The linear speed of a particle at the equator of the earth due to its spin motion is ' V '. The linear speed of the particle at latitude 30^ is [ array l 30^ = 60^ =1 / 2 30^ = 60^ = 3 / 2 array ]
Options
- AV 2
- BV 2
- C3 2 ~V
- DV
Correct answer
C. 3 2 ~V
Step-by-step solution
The particle on the equator of the earth has linear speed V . V=R ...(i) where R is the radius of the earth. If the particle is now at 30^ latitude, the particle will move in a circle of smaller radius. Let the radius of this smaller circle be r . r = R The linear velocity of the particle at 30^ , aligned V^ & =r & =R =R 30^ = 3 2 R aligned ...(ii) Dividing equation (ii) by (i), aligned & V^ V = 3 2 R R & V^ = & V 3 2 aligned