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MHT CET202311 May 2023Morning ShiftPhysicsGravitationActual

A body of mass ' m ' kg starts falling from a distance 3R above earth's surface. When it reaches a distance ' R ' above the surface of the earth of radius ' R ' and Mass ' M ', then its kinetic energy is

Options

  1. A2 3 GMm R
  2. B1 3 GMm R
  3. C1 2 GMm R
  4. D1 4 GMm R

Correct answer

D. 1 4 GMm R

Step-by-step solution

Initial height: h =3 R + R =4 R The potential energy of the body initially will be: U ₁=- 1 4 GMm R At the height R , h = R + R =2 R Potential energy: U ₂=- 1 2 GMm R Gain in kinetic energy is equal to loss in potential energy. aligned KE & = U ₁- U ₂ & =- 1 4 GMm R - (- 1 2 GMm R )= 1 4 GMm R aligned

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