MHT CET20227 Aug 2022Morning ShiftPhysicsGravitationActual
The escape velocity for a planet whose mass is six times the mass of earth and the radius is twice the radius of earth will be [ V _ e = . escape velocity from the earth ]
Options
- A2 ~V _ e
- B1 2 ~V _ e
- C3 ~V _ e
- D2 2 ~V _ e
Correct answer
C. 3 ~V _ e
Step-by-step solution
Escape velocity is defined using relation: aligned & 1 2 mv _ e ^2= GMm R & V _ e = 2 GM R aligned If M is replaced 6 M & R is replaced by 2 R then V _ e ^ = 3 ~V _ e