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MHT CET20226 Aug 2022Evening ShiftPhysicsGravitationActual

The escape velocity of a body from the surface of the earth is 11.2 ~km / s . The escape velocity of a body from a planet having same mean density as the earth but twice the radius of earth is

Options

  1. A5.5 ~km / s
  2. B33.6 ~km / s
  3. C22.4 ~km / s
  4. D11.2 ~km / s

Correct answer

C. 22.4 ~km / s

Step-by-step solution

For escape velocity the formula is, v_e= 2 G M R = 2 G ( 4 3 R^3 ) R = 8 3 G R^2 Where, is density of the planet and R is its radius. aligned & v_e=R 8 3 G & v_e R aligned So, the escape velocity on the planet would be 22.4 ~km / s .

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