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MHT CET2007PhysicsGravitation

A 500 ~kg car takes a round turn of radius 50 ~m with a velocity of 36 ~km / h . The centripetal force is

Options

  1. A250 ~N
  2. B750 ~N
  3. C1000 ~N
  4. D1200 ~N

Correct answer

C. 1000 ~N

Step-by-step solution

The centripetal force required for a car (mass m ) to take a sharp turn of radius r with velocity v is F= m v² r Given, m=500 ~kg , array l v=36 ~km / h =36 5 18 =10 ~m / s , r=50 ~m Hence, F= 500 (10)² 50 =1000 ~N array

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