An electron is moving with initial velocity v = V₀ j in a magnetic field B = B₀ i . Its de-Broglie wavelength will

Step-by-step solution

The magnetic force acting on a moving charge is given by F = q( v B ) . Since the magnetic force is always perpendicular to the velocity vector, the work done by the magnetic field on the electron is zero. According to the work-energy theorem, the kinetic energy of the electron remains constant, which implies its speed v remains constant. The de-Broglie wavelength is given by = h mv . Since the speed v is constant, the de-Broglie wavelength of the electron remains constant. Answer: remains constant.