Two wires with current 3A and 1.5A are enclosed in a circular loop P. Third parallel wire with current 1A is situated outside the loop as shown. All the wires are perpendicular to the plane of the circular loop. The value of B dl around the

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Two wires with current 3A and 1.5A are enclosed in a circular loop P. Third parallel wire with current 1A is situated outside the loop as shown. All the wires are perpendicular to the plane of the circular loop. The value of B dl around the loop is ( ₀ = permeability of free space)

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Correct answer: C. 1.5 , ₀

According to Ampere's circuital law, the line integral of the magnetic field B around any closed loop is equal to ₀ times the net current enclosed by the loop: B d l = ₀ I_ enclosed From the given figure, the loop P encloses two wires carrying currents 3 A (upwards) and 1.5 A (downwards). The third wire carrying 1 A is outside the loop and does not contribute to the enclosed current. Taking the upward direction as positive, the net enclosed current is: I_ enclosed = 3 - 1.5 = 1.5 A Therefore, the value of the integ

Two wires with current 3A and 1.5A are enclosed in a circular loop P. Third parallel wire with current 1A is situated outside the loop as shown. All the wires are perpendicular to the plane of the circular loop. The value of B dl around the loop is ( ₀ = permeability of free space)

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