A particle of charge ' q ' and mass ' m ' moves in a circular orbit of radius ' r ' with angular speed ' '. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends upon

Step-by-step solution

Magnetic moment of the revolving charge is given by M = IA Current I = q T = q 2 Area A = r^2 M = ( q 2 )( r^2) = 1 2 q r^2 Angular momentum of the particle is L = mvr = m( r)r = m r^2 The ratio of the magnitude of magnetic moment to that of angular momentum is M L = 1 2 q r^2 m r^2 = q 2m This ratio depends only on q and m . Answer: q and m