Two wires of equal lengths are bent in the form of a square and a circular loop. They are suspended in a uniform magnetic field and same current is passed through them. Torque experienced by

Step-by-step solution

The torque on a current loop in a uniform magnetic field is given by = NIAB . For identical current I and magnetic field B , with both loops optimally oriented ( = 1 ), the torque depends only on area A since N=1 . Using wire length L , the square side is s = L/4 with area A_ square = (L/4)^2 = L^2/16 . The circular loop has radius r = L/(2 ) and area A_ circle = r^2 = L^2/(4 ) . Comparing areas: L^2/(4 ) > L^2/16 since 4 12.566 _ square . Final answer: D