AP EAMCET202423 May 2024Morning ShiftMathematicsCircleActual
Consider the point P( , ) on the line 2 x+y=1 . If the P and (3,2) are conjugate points with respect to the circle x^2+y^2=4 , then + =
Options
- A3
- B-1
- C-5
- D7
Correct answer
A. 3
Step-by-step solution
Polar of point (3,2) w.r.t. circle x^2+y^2=4 is T₁=0 3 x+2 y=4 Since, (3,2) and P( , ) are conjugate point. So, polar of (3,2) passes through P( , ) 3 +2 =4 ...(i) Also, P( , ) lies on 2 x+y=1 2 + =1 ...(ii) Solving (i) and (ii), =-2, =5 + =-2+5=3 .