A wire of length L carries current I along x -axis. A magnetic field B =B₀( i - j - k ) T acts on the wire. The magnitude of magnetic force acting on the wire is

Step-by-step solution

The magnetic force on a current-carrying wire is given by F = I( L B ) . Given L = L i and B = B₀( i - j - k ) , the cross product evaluates to: L B = (L i ) B₀( i - j - k ) = LB₀[ i i - i j - i k ] Using i i = 0 , i j = k , and i k = - j , we obtain: L B = LB₀[- k - (- j )] = LB₀( j - k ) The force becomes F = ILB₀( j - k ) , with magnitude: | F | = ILB₀ 1^2 + (-1)^2 = 2 ILB₀ Final answer: D