MHT CET202520 Apr 2025Evening ShiftPhysicsMagnetic Effects of CurrentActual
An element = x i is placed at the origin and carries a current of 10A. The magnitude of magnetic field on the Y axis at a distance of 0.5 m if x =1 ~cm is ( ₀ 4 =10⁻⁷ . SI unit ) ( 90^ =1 )
Options
- A2 10⁻⁷ ~T
- B10⁻⁸ ~T
- C4 10⁻⁸ ~T
- D2 10⁻⁸ ~T
Correct answer
C. 4 10⁻⁸ ~T
Step-by-step solution
The magnitude of the magnetic field due to a current element is given by B = ₀ 4 I , d , r^2 . Given: I = 10 , A , d = 0.01 , m , r = 0.5 , m , and ₀ 4 = 10⁻⁷ , T m/A . The direction of the current element is along the x -axis while the field point lies on the y -axis, yielding = 90^ and = 1 . Substitute into the formula: B = 10⁻⁷ 10 0.01 1 0.5^2 = 10⁻⁷ 0.1 0.25 = 10⁻⁷ 0.4 = 4 10⁻⁸ , T . This result corresponds to option C .