MHT CET20249 May 2024Morning ShiftPhysicsMagnetic Effects of CurrentActual
The magnetic field intensity inside current carrying solenoid is H =2.4 10^3 ~A / m . If length and number of turns of a solenoid is 15 cm and 60 turns respectively. The current flowing in the solenoid is
Options
- A4 A
- B6 A
- C0.6 ~A
- D60 A
Correct answer
B. 6 A
Step-by-step solution
aligned & B= ₀ NI L & ₀ H = ₀ NI L & I= HL n = 2.4 10^3 15 10⁻² 60 =6 ~A aligned