A square loop of area 25 ~cm ^2 has a resistance of 10 . The loop is placed in uniform magnetic field of magnitude 40 T . The plane of loop is perpendicular to the magnetic field. The work done in pulling the loop out of the magnetic field slowly and uniformly in 1 second, will be

Step-by-step solution

Area of square is 25 ~cm ^2 length =5 ~cm =0.05 ~m Velocity, v = l t = 0.05 1 =0.05 ~m / s e = B / v IR = B / v I = B / v R = 40 0.05 0.05 10 =0.01 ~A Since magnetic field is perpendicular to plane of loop, =90^ aligned F & = BI l & =40 0.01 0.05 90=0.02 ~N ~W & = F l & =0.02 0.05=1 10⁻³ ~J aligned