MHT CET20244 May 2024Morning ShiftPhysicsMagnetic Effects of CurrentActual
A charged particle of charge ' q ' is accelerated by a potential difference ' V ' enters a region of uniform magnetic field ' B ' at right angles to the direction of field. The charged particle completes semicircle of radius ' r ' inside magnetic field. The mass of the charged particle is
Options
- Ar^2 q B^2 2 V
- Br^2 q^2 B^2 2 V
- Cq r B 2 ~V
- Dq^2 r^2 B^2 V
Correct answer
A. r^2 q B^2 2 V
Step-by-step solution
When charged particle enters perpendicular to a uniform magnetic field, then it follows a circular path. Its radius is given by, R= m v q B = 2 m E q B As the charged particle is accelerated through potential difference of V , K E = qV array ll & Substituting in (i), & R= 2 m q V q B = 2 m V q 1 B & R^2= 2 m V q 1 B^2 & m= R^2 q^2 2 V = r^2 q B^2 2 V array (given, R = r )