A square loop of area 25 ~cm ^2 has a resistance of 10 . This loop is placed in a uniform magnetic field of magnitude 40 ~T . The plane of loop is perpendicular to the magnetic field. The work done in pulling the loop out of the magnetic fi

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A square loop of area 25 ~cm ^2 has a resistance of 10 . This loop is placed in a uniform magnetic field of magnitude 40 ~T . The plane of loop is perpendicular to the magnetic field. The work done in pulling the loop out of the magnetic field slowly and uniformly in one second, will be

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Correct answer: B. 1.0 10⁻³ ~J

Given: area of square loop =25 ~cm array ll l= 25 =5 ~cm 0.05 ~m & R =10 , t =1 sec , B =40 ~T & Velocity v = l t = 0.05 1 =0.05 ~m / s & Motional emf _ = B / v & I = R = B / v R & I = 40 0.05 0.05 10 =0.01 ~A array We know, Force acting on loop aligned F = BI l & =40 0.01 0.05 & =0.02 ~N Using W = F . s , & Work done W & = BI l l & =0.02 0.05 & =1 10⁻³ ~J aligned

A square loop of area 25 ~cm ^2 has a resistance of 10 . This loop is placed in a uniform magnetic field of magnitude 40 ~T . The plane of loop is perpendicular to the magnetic field. The work done in pulling the loop out of the magnetic field slowly and uniformly in one second, will be

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