MHT CET202210 Aug 2022Morning ShiftPhysicsMagnetic Effects of CurrentActual
A charge moves in a circular path perpendicular to a magnetic field. The time period of the revolution is independent of
Options
- Astrength of charge.
- Bmagnetic field.
- Cmass of the charge.
- Dvelocity of the charge.
Correct answer
D. velocity of the charge.
Step-by-step solution
The time period of a charged particle undergoing circular motion under uniform perpendicular magnetic field is given by T= 2 m q B So, it is independent of velocity.