A proton moving in perpendicular magnetic field possess energy E . The strength of magnetic field is increases four times. But the proton is constrained to move in the path of same radius. The kinetic energy of proton will increase

Step-by-step solution

In orthogonal magnetic field, the changed particle undergoes uniform circular motion. aligned & m v^2 R =q v B & v^2 ( q B m ) r aligned If B increases by four times & r remains same aligned & v_ new ^2= [ ( q B m ) r ] 4=(2 v)^2 & K E_ new = 1 2 v_ new ^2= ( 1 2 m v^2 ) 4 aligned