In the current carrying conductor (AOCDEFG) as shown, the magnetic induction at the point O is ( R ₁ . and R ₂ are radii of are C D & E F respectively, I = current in the loop, ₀= permeability of free space)

Step-by-step solution

Using biot savart's law, it can be concluded that the magnetic field along the line of a straight current carrying conductor is zero. Hence, magnetic fields due to sections AO, OC, DE & FG are zero at point O . Magnetic field at the center of a current carrying loop is given by: B= ₀ I 2 R Hence, magnetic field due to section CD is: B _ CD = ( 1 4 ) ₀ I 2 R ₁ inside the plane of paper (using right hand thumb rule) Here, the factor 1 4 appears as only one fourth of the total circumference contributes to the magnetic