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AP EAMCET202421 May 2024Evening ShiftMathematicsCircleActual

If the equation of the circle whose radius is 3 units and which touches internally the circle x^2+y^2-4 x-6 y-12=0 at the point (-1,-1) is x^2+y^2+p x+q y+r=0 , then p+q-r=

Options

  1. A2
  2. B5 2
  3. C26 5
  4. D3

Correct answer

A. 2

Step-by-step solution

x^2+y^2+p x+q y+r=0 touches the given circle at (-1,-1) . Hence (-1)^2+(-1)^2-p-q+r=0 p+q-r=2 .

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