A particle having a charge 100 e is revolving in a circular path of radius 0.8 ~m with 1.r.p.s The magnetic field produced at the center of the circle in SI unit is ( ₀ permeability of vacuum, . e =1.6 10⁻¹⁹ C )

Step-by-step solution

The magnetic field produced by a circular coil of radius r at its centre is given by B = ₀ I 2 r In this case r=0.8 ~m Frequency f =1 r.p.s. aligned & I = qf =100 e A & B = ₀ 100 e 2 0.8 = ₀ 100 1.6 10⁻¹⁹ 1.6 & =10⁻¹⁷ ₀ aligned