The pole of the straight line 9 x+y-28=0 with respect to the circle 2 x^2+2 y^2-3 x+5 y-7=0 is

Step-by-step solution

Let (h, k) be the pole 9 x+y-28=0 with respect to given circle 2 x^2+2 y^2-3 x+5 y-7=0 Then equation of polar is T=0 aligned & 2 h x+2 k y- 3(h+x) 2 + 5(k+y) 2 -7=0 & (2 h- 3 2 ) x+ (2 k+ 5 2 ) y+ 5 k-3 h-14 2 =0 aligned On comparing with 9 x+y-28=0 , we get 2 h- 3 2 9 = 2 k+ 5 2 1 = 5 k-3 h-14 -2 28 On solving we get (h, k)=(3,-1) .