Two identical thin bar magnets are placed mutually at right angles such that the north pole of one touches the south pole of the other. The length of each bar magnet is ' ^ . The magnitude of resultant magnetic moment of the system is [ m = pole strength of the pole of magnet ]

Step-by-step solution

Given that, Length of bar magnet = L Pole strength = m Let the pole strength of the system magnets be m and length N₂ S₁ But, array l N ₂ ~S ₁= ( N ₁ ~S ₁ )²+ ( N ₂ ~S ₂ )² ~N ₁ ~S ₁= N ₂ ~S ₂= L N ₂ ~S ₁= L ²+ L ² ~N ₂ ~S ₁= L 2 array Magnetic moment of the system array l M = m N ₂ ~S ₁ M = m L 2 M = mL 2 array Hence, the Magnetic moment of the system is mL 2