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MHT CET202618 April 2026Morning ShiftPhysicsMathematics in PhysicsActual

If two resistors of resistances have values R₁ = (350 3) and R₂ = (140 4) . The percentage error for the sum and difference of R₁ and R₂ are respectively

Options

  1. A1.43 % , 3.33 %
  2. B7 % , 1 %
  3. C1 % , 7 %
  4. D3.33 % , 1.43 %

Correct answer

A. 1.43 % , 3.33 %

Step-by-step solution

Given R₁ = (350 3) and R₂ = (140 4) . For the sum of resistances: R_s = R₁ + R₂ = 350 + 140 = 490 The absolute error in the sum is the sum of absolute errors: R_s = R₁ + R₂ = 3 + 4 = 7 Percentage error in sum = R_s R_s 100 = 7 490 100 = 100 70 1.43 % For the difference of resistances: R_d = R₁ - R₂ = 350 - 140 = 210 The absolute error in the difference is also the sum of absolute errors: R_d = R₁ + R₂ = 3 + 4 = 7 Percentage error in difference = R_d R_d 100 = 7 210 100 = 100 30 3.33 % The percentage errors are 1.43

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