AP EAMCET202420 May 2024Morning ShiftMathematicsCircleActual
Let be an integer multiple of 8 . If 5 is the set or an possible values of such that the line 6 x+8 y+ =0 intersects the circle x^2+y^2-4 x-6 y+9=0 at two distinct points, then the number of elements in S is
Options
- A4
- B6
- C2
- D1
Correct answer
A. 4
Step-by-step solution
x^2+y^2-4 x-6 y+9=0 Radius = 4+9-9 =2 ; Centre =(2,3) The line 6 x+8 y+ =0 intersects the circle at two distinct points Length of Perpendicular from centre radius | 12+24+ 10 | -56 -16 Since, =8 k where k Z -56 8 k -16 -7 k -2 Possible radius of k=-3,-4,-5,-6 Number of elements in S=4