A wire has mass (0.3 0.003) gram, radius (0.5 0.005) cm and length (6 0.06) cm. The maximum percentage error in the measurement of density is

Step-by-step solution

Density of the wire is given by = m r^2 l The maximum percentage error in density is 100 = ( m m + 2 r r + l l ) 100 Substituting the given values: 100 = ( 0.003 0.3 + 2 0.005 0.5 + 0.06 6 ) 100 100 = (0.01 + 2 0.01 + 0.01) 100 100 = 0.04 100 = 4 , % Answer: 4 , %