A wire has mass (0.3 0.003) gram, radius (0.5 0.005) mm and length (6 0.06) cm. The maximum error in the measurement of density is

Step-by-step solution

Density of the wire is given by = m r^2 l The maximum percentage error in density is 100 = ( m m + 2 r r + l l ) 100 Given values are: m m 100 = 0.003 0.3 100 = 1 % r r 100 = 0.005 0.5 100 = 1 % l l 100 = 0.06 6 100 = 1 % Substituting these values, we get: 100 = 1 % + 2(1 %) + 1 % = 4 % Answer: 4 %