MHT CET202615 April 2026Morning ShiftPhysicsMathematics in PhysicsActual
The length of rod is measured by meter scale having least count 0.1 cm and diameter is measured by vernier callipers having least count 0.01 cm. Length of rod is 5.0 cm and radius 2.0 cm. The percentage error in the calculated value of the volume is
Options
- A1 %
- B2.5 %
- C5 %
- D7 %
Correct answer
B. 2.5 %
Step-by-step solution
The volume of the cylindrical rod is given by V = D^2 L 4 , where D is the diameter and L is the length. The percentage error in the volume is given by: V V 100 = ( 2 D D + L L ) 100 Given that the diameter is measured by vernier callipers, the measured quantity is D . Radius r = 2.0 cm Diameter D = 4.0 cm Least count of vernier callipers, D = 0.01 cm Length L = 5.0 cm Least count of meter scale, L = 0.1 cm Substituting the values into the percentage error formula: V V 100 = ( 2 0.01 4.0 + 0.1 5.0 ) 100 V V 100 = (