If the equation of the circle passing through the points of intersection of the circles

Step-by-step solution

S₁=x^2-2 x+y^2-4 y-4=0S₂=x^2+2 x+y^2+4 y-4=0 Equation of circle passing through intersection of S ₁ and S ₂ is S₁+ S₂=0 aligned (1+ ) x^2+2( -1) x+(1+ ) y^2+4( -1) y-4-4 =0 aligned Also it passes (3,3) 9(1+ )+6( -1)+9(1+ )+12( -1)-4-4 =0 18(1+ )+18( -1)-4-4 =0 = 1 8 Now, = 2( -1) (1+ ) = -14 9 = 4( -1) (1+ ) = -28 9 = -4( +1) (1+ ) =-4 ; Now, 3( + + )=3 ( -78 9 )=-26