Vector A of magnitude 5 3 units, another vector B of magnitude of 10 units are inclined to each other at an angle of 30^ . The magnitude of vector product of the two vectors is [ 30^ = 1 2 ]

Step-by-step solution

Vector product magnitude is determined by | A B | = AB . Given A = 5 3 , B = 10 , and = 30^ where 30^ = 1 2 : | A B | = (5 3 )(10) ( 1 2 ) = 25 3 units. This result corresponds to option C .