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AP EAMCET202418 May 2024Morning ShiftMathematicsCircleActual

If Q (h, k) is the inverse point of the point P (1,2) with respect to the circle x^2+y^2-4 x+1-0 , then 2 h+k=

Options

  1. A3
  2. B4
  3. C7
  4. D11

Correct answer

B. 4

Step-by-step solution

Given equation of circle x^2+y^2-4 x+1=0 (x-2)^2+y^2=3 . So, centre =(2,0) , radius = 3 Now, inverse point is h = (1-2)+2 k= (2-0)+0 where, = r^2 (1-2)^2+(2-0)^2 = 3 1+4 = 3 5 Now, h= 3 5 (1-2)+2= -3 5 +2= 7 5 and k= 3 5 (2)= 6 5 So, 2 h+k= 14 5 + 6 5 = 20 5 =4

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