An incompressible fluid (ideal fluid) is flowing through non uniform cross-sectional tube PQ as shown in the figure from end P to end Q. If K_P and K_Q are the kinetic energy per unit volume of the fluid at end P and end Q respectively, then

Step-by-step solution

From the given figure, the cross-sectional area of the tube at end P is less than the cross-sectional area at end Q, so A_P According to the equation of continuity for an incompressible fluid, the product of cross-sectional area and velocity remains constant: A_P v_P = A_Q v_Q Since A_P v_Q . The kinetic energy per unit volume of the fluid is given by K = 1 2 v^2 , where is the density of the fluid. Since v_P > v_Q , it follows that v_P^2 > v_Q^2 . Therefore, 1 2 v_P^2 > 1 2 v_Q^2 , which implies K_P > K_Q . Answer