In a capillary tube of area of cross-section ' a ' water rises to height ' h '. To what height will water rise in a capillary tube of area of cross-section 4a ?

Step-by-step solution

The height of capillary rise is given by h = 2T g r This implies h 1 r The area of cross-section is a = r^2 , which gives r a Therefore, h 1 a Using the relation for two different tubes, we get h₁ a₁ = h₂ a₂ Substituting the given values, h a = h' 4a h a = h' (2 a ) h' = h 2 Answer: h 2