Water rises to a height 3 cm in a capillary tube. If cross-sectional area of capillary tube is reduced to 1/3^ rd of its initial area then water will rise to a height of

Step-by-step solution

The height of water in a capillary tube is given by h = 2T g r This implies h 1 r Given that the cross-sectional area is reduced to 1 3 of its initial value: A₂ = A₁ 3 r₂^2 = r₁^2 3 r₂ = r₁ 3 Using the relation h₁ r₁ = h₂ r₂ : h₂ = h₁ r₁ r₂ h₂ = 3 3 = 3 3 cm Answer: 3 3 cm