Water rises in a capillary tube of radius r upto a height h . The mass of water in a capillary is m . The mass of water that will rise in capillary of radius r 5 will be

Step-by-step solution

The height to which water rises in a capillary tube of radius r is given by h = 2T g r , where T is surface tension, is the contact angle, is density, and g is gravitational acceleration. Therefore, h 1 r , so hr is constant. The mass of water in the capillary is m = V = r^2 h . Substituting h = constant r , we obtain m = r^2 ( constant r ) = ( constant ) r . Thus, m r . For a new radius r₂ = r 5 , the mass m₂ satisfies m₂ m = r₂ r = 1 5 . Consequently, m₂ = m 5 . The mass of water that rises in the capillary of ra