There are two identical small holes on the opposite side of a tank containing full of a liquid. The tank is open at the top. The difference in height between the two holes is ' h '. As the liquid comes out of the two holes, the tank will experience a net horizontal force proportional to

Step-by-step solution

The thrust force from each hole follows from the rate of momentum efflux. For a hole at depth h' , the efflux velocity is v = 2gh' , yielding a thrust F = A v^2 = 2 A g h' in the direction opposite to the outflow. The upper hole at depth h₁ produces leftward thrust F₁ = 2 A g h₁ , while the lower hole at depth h₂ produces rightward thrust F₂ = 2 A g h₂ . With h₂ - h₁ = h , the net rightward force is F_ net = F₂ - F₁ = 2 A g (h₂ - h₁) = 2 A g h . This establishes F_ net h , confirming option D.