Two capillary tubes of same diameter are kept vertically in two liquids whose densities are in the ratio 4: 3 . If their surface tensions are in the ratio 6:5, the ratio of heights ( h₁ h₂ ) of liquids in the two capillary tubes is (Their angle of contacts are same)

Step-by-step solution

The equilibrium height h for capillary action is given by the capillary rise equation: h = 2T r g Since both tubes have identical diameters and angle of contact, all parameters except T and cancel in the height ratio: h₁ h₂ = T₁ T₂ ₂ ₁ Substituting the given ratios T₁ T₂ = 6 5 and ₁ ₂ = 4 3 ₂ ₁ = 3 4 : h₁ h₂ = 6 5 3 4 = 18 20 = 9 10 This corresponds to option B .