The surface energy of a liquid drop is "V". It is sprayed into 1000 equal droplets. The surface energy of all the droplets is

Step-by-step solution

Let R be the initial radius and A = 4 R^2 the initial surface area of the liquid drop. Given the surface energy V = T 4 R^2 , where T is the surface tension. The drop is sprayed into 1000 equal droplets, each with radius r . Since the volume remains constant: 4 3 R^3 = 1000 4 3 r^3 Simplifying gives R^3 = 1000r^3 , thus R = 10r and r = R/10 . The total surface area of the droplets becomes: A' = 1000 4 r^2 = 1000 4 (R/10)^2 = 1000 4 R^2/100 = 10A The new surface energy is therefore: V' = T A' = T 10A = 10V The total