A lead sphere of mass ' m ' falls in viscous liquid with terminal velocity V ₀ . Another lead sphere of mass ' 8 m ' but of same material will fall through the same liquid with terminal velocity

Step-by-step solution

The formula for terminal velocity for a spherical body V= 2 g( - ) r^2 2 If mass is made 8 times, material being same volume also becomes 8 times density is same. So, radius of sphere becomes twice. The new terminal velocity aligned & V₀ V₂ = ( r₁ r₂ )^2 & V₀ V₂ = ( I 2 )^2 & V₂=4 V_ aligned