A big water drop is formed by the combination of ' n ' small water droplets of equal radii. The ratio of the surface energy of ' n ' droplets to the surface energy of the big drop is

Step-by-step solution

Let R be the radius of bigger drop and r be the radius of single small water drop. Volume of big drop =n( Volume of small drop ) aligned & 4 3 R^3=n 4 3 r^3 & R^3=n r^3 & R=n^ 1 3 r aligned Surface energy of n drops (E_n )=n 4 r^2 T Surface energy of big drop (E)=4 R^2 T E_n E = n r^2 R^2 = n r^2 (n^ 1 3 r )^2 = n r^2 n^ 2 3 r^2 =n^ 1 3 = [3] n : 1