MHT CET20249 May 2024Evening ShiftPhysicsMechanical Properties of FluidsActual
The work done in splitting a water drop of radius R into 64 droplets is ( T = Surface tension of water)
Options
- A6 TR ^2
- B12 TR ^2
- C8 TR ^2
- D24 TR ^2
Correct answer
B. 12 TR ^2
Step-by-step solution
Given the radius of drop is R . Let r be the radius of smaller droplets. As the total volume remains the same, array ll & 4 3 R^3=64 4 3 r^3 & r= R (64)^ 1 3 = R 4 array Initial surface energy E₁=4 R^2 T Final surface energy E₂=64 4 ( R 4 )^2 T=16 R ^2 ~T Work done, W = E ₂- E ₁ W =12 TR ^2