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MHT CET20244 May 2024Evening ShiftPhysicsMechanical Properties of FluidsActual

A hemispherical portion of radius ' R ' is removed from the bottom of a cylinder of radius ' R '. The volume of the remaining cylinder is ' V ' and its mass is ' M '. It is suspended by a string in a liquid of density ' ' where it stays vertical. The upper surface of the cylinder is at a depth ' h ' below the liquid surface. The force on the bottom of the liquid is

Options

  1. AMg
  2. BMg - V g
  3. CMg + R ^2 ~h g
  4. Dg (V+ r^2 h )

Correct answer

D. g (V+ r^2 h )

Step-by-step solution

Net upward zone force on the bottom of the liquid = weight of the liquid displaced by cylinder + thrust force on upper surface of the cylinder due to h column of liquid aligned & F_ net = V g+ g h r^2 &= g (V+ r^2 h ) aligned

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