The pressure inside a soap bubble A is 1.01 atmosphere and that in a soap bubble B is 1.02 atmosphere. The ratio of volume of bubble A to that of B is [Surrounding pressure =1 atmosphere ]

Step-by-step solution

Outside pressure =1 ~atm Pressure inside first bubble =1.01 ~atm Pressure inside second bubble =1.02 ~atm Excess pressures will be P ₁=1.01-1=0.01 ~atm and P ₂=1.02-1=0.02 ~atm array ll & Now, P 1 r r 1 P & r ₁ r ₂ = P ₂ P ₁ = 0.02 0.01 = 2 1 & Now, V = 4 3 r ^3 & ~V r ^3 & ~V ₁ ~V ₂ = ( r ₁ r ₂ )^3= ( 2 1 )^3= 8 1 array